std::is_compound

From Cppreference

If T is a compound type (that is, array, function, object pointer, function pointer, member object pointer, member function pointer, reference, class, union, or enumeration, including any cv-qualified variants), provides the member constant value equal true. For any other type, value is false.

[edit] Notes

Compound types are the types that are constructed from fundamental types. Any C++ type is either fundamental or compound.

[edit] Equivalent definition

template< class T >
struct is_compound : std::integral_constant<bool, !std::is_fundamental<T>::value> {};

[edit] Example

#include <iostream>
#include <type_traits>
 
int main() {
    class cls {};
    std::cout << (std::is_compound<cls>::value
                     ? "T is compound"
                     : "T is not a compound") << '\n';
    std::cout << (std::is_compound<int>::value
                     ? "T is compound"
                     : "T is not a compound") << '\n';
}

Output:

T is compound
T is not a compound

[edit] See also